document.write( "Question 355014: Train A is leaving Austin to Houston at 82.1 miles per hour.Tran B leaves to Austin at 109.071 miles per hour. How long before they pass eachother on the 240 mile trip ? How far from Austin will they pass ? \n" ); document.write( "
Algebra.Com's Answer #253576 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Train A is leaving Austin to Houston at 82.1 miles per hour. \n" ); document.write( "Train B leaves to Austin at 109.071 miles per hour. \n" ); document.write( "distance between the two cities = 240 miles..\r \n" ); document.write( "\n" ); document.write( ".. \n" ); document.write( "let distance from Austin be x miles \n" ); document.write( "distance from houston = 240-x miles. \n" ); document.write( "... \n" ); document.write( "time = distance / speed \n" ); document.write( ".. \n" ); document.write( "when they both meet the time they have travelled is the same. \n" ); document.write( "Train A time to meet = x/82.1 \n" ); document.write( "Train B time to meet = 240-x/109.071 \n" ); document.write( ".. \n" ); document.write( "x/82.1 = 240-x/109.071 \n" ); document.write( "109.071x=82.1(240-x) \n" ); document.write( "109.071x= 19704 -82.1x \n" ); document.write( "109.071x+82.1x = 19704 \n" ); document.write( "191.171x=19704 \n" ); document.write( "x=103.07 miles from austin. \n" ); document.write( "speed of Train A = 82.1 \n" ); document.write( "time taken to meet = 103.07/82.1 \n" ); document.write( "= 1.256 hours. \n" ); document.write( "They meet after 1.256 hours \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |