document.write( "Question 355014: Train A is leaving Austin to Houston at 82.1 miles per hour.Tran B leaves to Austin at 109.071 miles per hour. How long before they pass eachother on the 240 mile trip ? How far from Austin will they pass ? \n" ); document.write( "
Algebra.Com's Answer #253576 by mananth(16946)\"\" \"About 
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Train A is leaving Austin to Houston at 82.1 miles per hour.
\n" ); document.write( "Train B leaves to Austin at 109.071 miles per hour.
\n" ); document.write( "distance between the two cities = 240 miles..\r
\n" ); document.write( "\n" ); document.write( "..
\n" ); document.write( "let distance from Austin be x miles
\n" ); document.write( "distance from houston = 240-x miles.
\n" ); document.write( "...
\n" ); document.write( "time = distance / speed
\n" ); document.write( "..
\n" ); document.write( "when they both meet the time they have travelled is the same.
\n" ); document.write( "Train A time to meet = x/82.1
\n" ); document.write( "Train B time to meet = 240-x/109.071
\n" ); document.write( "..
\n" ); document.write( "x/82.1 = 240-x/109.071
\n" ); document.write( "109.071x=82.1(240-x)
\n" ); document.write( "109.071x= 19704 -82.1x
\n" ); document.write( "109.071x+82.1x = 19704
\n" ); document.write( "191.171x=19704
\n" ); document.write( "x=103.07 miles from austin.
\n" ); document.write( "speed of Train A = 82.1
\n" ); document.write( "time taken to meet = 103.07/82.1
\n" ); document.write( "= 1.256 hours.
\n" ); document.write( "They meet after 1.256 hours
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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