document.write( "Question 355000: I need to solve the equation by completing the square. The following is my work but I get the wrong answer. Please let me know where I went wrong.\r
\n" ); document.write( "\n" ); document.write( "x^2 - 6x +3 = 0
\n" ); document.write( "x^2 -6x = -3
\n" ); document.write( "x^2 -6x -3^2 = -3-3^2
\n" ); document.write( "x^2 - 6x = -12
\n" ); document.write( "(x-6)^2 = sqrt -12
\n" ); document.write( "x-6 = sqrt -12
\n" ); document.write( "x=6+sqrt -12 and x = 6 - sqrt-12
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Algebra.Com's Answer #253560 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First, let's complete the square for the expression \"x%5E2-6x%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-6x%2B3\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "Take half of the \"x\" coefficient \"-6\" to get \"-3\". In other words, \"%281%2F2%29%28-6%29=-3\".\r
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\n" ); document.write( "\n" ); document.write( "Now square \"-3\" to get \"9\". In other words, \"%28-3%29%5E2=%28-3%29%28-3%29=9\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-6x%2Bhighlight%289-9%29%2B3\" Now add and subtract \"9\". Make sure to place this after the \"x\" term. Notice how \"9-9=0\". So the expression is not changed.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-6x%2B9%29-9%2B3\" Group the first three terms.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-3%29%5E2-9%2B3\" Factor \"x%5E2-6x%2B9\" to get \"%28x-3%29%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-3%29%5E2-6\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So after completing the square, \"x%5E2-6x%2B3\" transforms to \"%28x-3%29%5E2-6\". So \"x%5E2-6x%2B3=%28x-3%29%5E2-6\".\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E2-6x%2B3=0\" is equivalent to \"%28x-3%29%5E2-6=0\".\r
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\n" ); document.write( "\n" ); document.write( "Now let's solve \"%28x-3%29%5E2-6=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-3%29%5E2-6=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-3%29%5E2=0%2B6\"Add \"6\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-3%29%5E2=6\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"x-3=%22%22%2B-sqrt%286%29\" Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x-3=sqrt%286%29\" or \"x-3=-sqrt%286%29\" Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( "\"x=3%2Bsqrt%286%29\" or \"x=3-sqrt%286%29\" Add \"3\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=3%2Bsqrt%286%29\" or \"x=3-sqrt%286%29\".\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r
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\n" ); document.write( "\n" ); document.write( "Jim
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