document.write( "Question 354981: Bill leaves Histown at 11:30 am and drives towards Hertown, 86 miles away, at 55 mph. Sue leaves Hertown at 12:45 and drives towards Histown at 60 mph.\r
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Algebra.Com's Answer #253557 by stanbon(75887)\"\" \"About 
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Bill leaves Histown at 11:30 am and drives towards Hertown, 86 miles away, at 55 mph. Sue leaves Hertown at 12:45 and drives towards Histown at 60 mph.
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\n" ); document.write( "Bill DATA:
\n" ); document.write( "rate = 55 mph ; time = x hrs ; distance = rt = 55x miles
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\n" ); document.write( "Sue DATA:
\n" ); document.write( "rate = 60 mph ; time = (x-(5/4)) hrs ; distance = 60(x-(5/4)) miles\r
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\n" ); document.write( "Equation:
\n" ); document.write( "distance + distance = 86 miles
\n" ); document.write( "55x + 60x - 5*15 = 86
\n" ); document.write( "115x = 161
\n" ); document.write( "x = 1.4 hrs (Time they meet will be 11:30+ 1.4 hrs = 12:54 pm
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\n" ); document.write( "The meeting point will be 1.4(55) = 77 miles from Histown.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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