document.write( "Question 354971: yes! i need help with this problem the sum of two consecutive terms in the arithmetic sequence 1,4,7,10,,, is 299 find these two terms? thank you! \n" ); document.write( "
Algebra.Com's Answer #253553 by jrfrunner(365)\"\" \"About 
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since the difference between any two numbers is constant, that defines this sequence as arithmetic.
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\n" ); document.write( "The \"nth\" term is defined as \"a%5Bn%5D=a%5B1%5D%2Bdelta%2A%28n-1%29\"
\n" ); document.write( "where \"a%5B1%5D=1\" (ie the first term and \"delta\"=difference between consecutive terms \"delta=3\" in this sequence
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\n" ); document.write( "so... \"a%5Bn%5D=a%5B1%5D%2Bdelta%2A%28n-1%29=1%2B3%28n-1%29=3n-2\"
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\n" ); document.write( "sum of two consecutive terms: \"a%5Bn%5D%2Ba%5Bn%2B1%5D=%283n-2%29%2B%283%28n%2B1%29-2%29=299\"
\n" ); document.write( "therefore
\n" ); document.write( "3n-2+3n+3-2=299
\n" ); document.write( "6n-1=299
\n" ); document.write( "6n=300
\n" ); document.write( "n=50
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\n" ); document.write( "\"a%5Bn%5D=3n-2\"=3*(50)-2=148
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\n" ); document.write( "\"a%5Bn%2B1%5D=3%28n%2B1%29-2=3%2851%29-2=151\"
\n" ); document.write( "==
\n" ); document.write( "validate\r
\n" ); document.write( "\n" ); document.write( "148+151=299
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