document.write( "Question 354820: The question is: If sin(2x)-cos(2x)=sqrt(2)sin(2x+xpi), then the number 0 < A < 2. What does A equal?\r \n" );
document.write( "\n" );
document.write( "I can't quite find the right trig identities to get the answer. \n" );
document.write( "This is what I've done so far, any help or pointers is much appreciated!\r \n" );
document.write( "\n" );
document.write( "I've started with the left side to attempt to make it look like the right side which will in the end, give me what A equals.\r \n" );
document.write( "\n" );
document.write( "2sin(x)cos(x) - cos^2 - sin^2(x)\r \n" );
document.write( "\n" );
document.write( "2sin(x)cos(x) -(1-sin^2(x)) - sin^2(x)\r \n" );
document.write( "\n" );
document.write( "2sin(x)cos(x) - 1 + sin^2(x) - sin^2(x)\r \n" );
document.write( "\n" );
document.write( "2sin(x)cos(x) -1\r \n" );
document.write( "\n" );
document.write( "This is where I'm stuck and have tried other trig identities but never wind up with the right answer. \n" );
document.write( "
![\"\"](\"/images/stars/iconNewId_16x16.gif\")
