document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=354971>Question 354971</A>: <I><SPAN STYLE=\"word-break: break-all;\"> yes! i need help with this problem the sum of two consecutive terms in the arithmetic sequence 1,4,7,10,,, is 299 find these two terms? thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253551 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253551\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "asubn = asub1 + (n-1)d<BR>\n" );
document.write( "asub(n+1) = asub1 + nd.<BR>\n" );
document.write( "Adding corresponding sides,<BR>\n" );
document.write( "asubn + asub(n+1) = 2asub1 + (2n-1)d.<BR>\n" );
document.write( "then<BR>\n" );
document.write( "299 = 2asub1 + (2n-1)d<BR>\n" );
document.write( "299 = 2*(1) + (2n-1)*3<BR>\n" );
document.write( "299 = 2 + (2n-1)3<BR>\n" );
document.write( "297 = (2n-1)3<BR>\n" );
document.write( "99 = 2n-1<BR>\n" );
document.write( "100 = 2n<BR>\n" );
document.write( "n = 50.<BR>\n" );
document.write( "so its the 50th term (148) and the 51st term (151). </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );