document.write( "Question 354897: michael is twice as old as maggie. nine years ago, michael was 5 times as old as maggie. how old is each now? \n" ); document.write( "
Algebra.Com's Answer #253524 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let maggie be x years \n" ); document.write( "Michael is 2x years \n" ); document.write( ".. \n" ); document.write( "9 years ago their ages were \n" ); document.write( "maggie = x-9 \n" ); document.write( "michael = 2x-9 \n" ); document.write( ".. \n" ); document.write( "2x-9=5(x-9) \n" ); document.write( "2x-9=5x-45 \n" ); document.write( "5x-2x=45-9 \n" ); document.write( "3x=42 \n" ); document.write( "/3 \n" ); document.write( "x=14 years, maggie's age \n" ); document.write( "Michael will be 2x = 2*14 = 28 years \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |