document.write( "Question 354897: michael is twice as old as maggie. nine years ago, michael was 5 times as old as maggie. how old is each now? \n" ); document.write( "
Algebra.Com's Answer #253524 by mananth(16946)\"\" \"About 
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let maggie be x years
\n" ); document.write( "Michael is 2x years
\n" ); document.write( "..
\n" ); document.write( "9 years ago their ages were
\n" ); document.write( "maggie = x-9
\n" ); document.write( "michael = 2x-9
\n" ); document.write( "..
\n" ); document.write( "2x-9=5(x-9)
\n" ); document.write( "2x-9=5x-45
\n" ); document.write( "5x-2x=45-9
\n" ); document.write( "3x=42
\n" ); document.write( "/3
\n" ); document.write( "x=14 years, maggie's age
\n" ); document.write( "Michael will be 2x = 2*14 = 28 years
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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