document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4948>Question 4948</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write a formula that expresses the relationship described below. Match your result to the correct answer below.<BR>\n" );
document.write( "r varies as t and r = –4 when t = 2. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2535 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2535\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First write the equation, where r and t are variables and k is a constant to be determined:<BR>\n" );
document.write( "r=kt\r<BR>\n" );
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document.write( "Plug in the values of r= -4 and t= 2:<BR>\n" );
document.write( "r= kt<BR>\n" );
document.write( "-4 = k* 2\r<BR>\n" );
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document.write( "Divide both sides by 2, and get <BR>\n" );
document.write( "-2 = k\r<BR>\n" );
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document.write( "Now substitute that value of k=-2 into the original equation:<BR>\n" );
document.write( "r=kt<BR>\n" );
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document.write( "R^2 at SCC\r<BR>\n" );
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document.write( " </SPAN>\n" );
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