document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39888>Question 39888</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help with this!\r<BR>\n" );
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document.write( "sqrt 4x + 1 + 3 = 0\r<BR>\n" );
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document.write( "The 4x+1 is inside the radical sign - the +3 = 0 is not.<BR>\n" );
document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25348 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25348\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay we have<BR>\n" );
document.write( "sqrt(4x + 1) + 3 = 0<BR>\n" );
document.write( "sqrt(4x + 1) = -3<BR>\n" );
document.write( "now square both sides<BR>\n" );
document.write( "4x + 1 = 9<BR>\n" );
document.write( "4x = 8<BR>\n" );
document.write( "x = 2<BR>\n" );
document.write( "now check it...<BR>\n" );
document.write( "it doesn't work because the principal root of 9 is regular three...<BR>\n" );
document.write( "thus, no solution... </SPAN>\n" );
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