document.write( "Question 354728: a solution containing 40% alcohol is to be mixed with a solution containing 75% alcohol. How much of each solution should be used to make 100 mL of a mixture that is 50% alcohol? \n" ); document.write( "
Algebra.Com's Answer #253473 by checkley77(12844)\"\" \"About 
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.75X+.40(100-X)=.50*100
\n" ); document.write( ".75X+40-.40X=50
\n" ); document.write( ".35X=50-40
\n" ); document.write( ".35X=10
\n" ); document.write( "X=10/.35
\n" ); document.write( "X=28.57 ML. OF 75% SOLUTION.
\n" ); document.write( "100-28.57=71.43 ML. OF 40% SOLUTION.
\n" ); document.write( "PROOF:
\n" ); document.write( ".75*28.57+40*71.43=.50*100
\n" ); document.write( "21.43+28.57=50
\n" ); document.write( "50=50
\n" ); document.write( "
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