document.write( "Question 354728: a solution containing 40% alcohol is to be mixed with a solution containing 75% alcohol. How much of each solution should be used to make 100 mL of a mixture that is 50% alcohol? \n" ); document.write( "
Algebra.Com's Answer #253473 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .75X+.40(100-X)=.50*100 \n" ); document.write( ".75X+40-.40X=50 \n" ); document.write( ".35X=50-40 \n" ); document.write( ".35X=10 \n" ); document.write( "X=10/.35 \n" ); document.write( "X=28.57 ML. OF 75% SOLUTION. \n" ); document.write( "100-28.57=71.43 ML. OF 40% SOLUTION. \n" ); document.write( "PROOF: \n" ); document.write( ".75*28.57+40*71.43=.50*100 \n" ); document.write( "21.43+28.57=50 \n" ); document.write( "50=50 \n" ); document.write( " |