document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=354714>Question 354714</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve 2x to the 2/3rds, plus 3x to the 1/3rd minus 2 = Zero? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253472 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253472\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^(2/3) is the square of x^(1/3)\r<BR>\n" );
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document.write( "let n=x^(1/3)\r<BR>\n" );
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document.write( "2n^2 + 3n - 2 = 0\r<BR>\n" );
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document.write( "factoring ___ (2n - 1)(n + 2) = 0\r<BR>\n" );
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document.write( "n = 1/2 ___ x^(1/3) = 1/2 ___ x = 1/8\r<BR>\n" );
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document.write( "n = -2 ___ x^(1/3) = -2 ___ x = -8 </SPAN>\n" );
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