document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39893>Question 39893</A>: <I><SPAN STYLE=\"word-break: break-all;\"> help!\r<BR>\n" );
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document.write( "Please show steps, I don't understand! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25345 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25345\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay, from<BR>\n" );
document.write( "x sqrt(18) - 3 sqrt(8x^2)<BR>\n" );
document.write( "The idea is to factor the roots out into perfect squares and what's left over, for example sqrt(18) = sqrt(9)*sqrt(2) = 3*sqrt(2)...<BR>\n" );
document.write( "Also sqrt(8x^2) = sqrt(4x^2)*sqrt(2) = 2x*sqrt(2)<BR>\n" );
document.write( "So if we put it together, we have<BR>\n" );
document.write( "x sqrt(18) - 3 sqrt(8x^2) =<BR>\n" );
document.write( "3x*sqrt(2) - 6x*sqrt(2) =<BR>\n" );
document.write( "-3x*sqrt(2) </SPAN>\n" );
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