document.write( "Question 354753: In a chemistry class, 5 liters of a 6% silver iodide solution must be mixed with an 8% solution to get a 7% solution. How many liters of the 10% solution are needed? \n" ); document.write( "
Algebra.Com's Answer #253449 by checkley77(12844)\"\" \"About 
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You have a mix of a 6% solution & an 8% solution.
\n" ); document.write( "Where is the 10% solution???
\n" ); document.write( "Maybe you meant 10 liters?
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\n" ); document.write( ".08x+.06(10-x)=/.07*10
\n" ); document.write( ".08x+.6-.06x=.7
\n" ); document.write( ",02x=,7-.6
\n" ); document.write( ".02x=.1
\n" ); document.write( "x=.1/.02
\n" ); document.write( "x=5 ans. for the amount of 8% solutio used.
\n" ); document.write( "Proof:
\n" ); document.write( ".08*5+.06*5=.07*10
\n" ); document.write( ".04+.03=.07
\n" ); document.write( ".07=.07
\n" ); document.write( "5 liters of 6% if mixed with 5 liters of 8% yields 10 liters of a 7% solution.
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