document.write( "Question 354730: We have been working on factoring trinomials and the problem I don't know how to solve is (x^2+4x-4)^2=64. I think what we're supposed to do is divide the exponent off both sides but I'm not sure. Were I get stuck is you're left with x^2+4x-4 on one side and that doesn't facter into two binomials. HELP ME! \n" ); document.write( "

Algebra.Com's Answer #253446 by Edwin McCravy(20055) $\"\"$ $\"About$

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$\"%28x%5E2%2B4x-4%29%5E2=64\"$
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document.write( "We use the principle of square roots:\r\n" );
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document.write( "Take away the square on the right, take ą square roots of the right side\r\n" );
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document.write( "Make two equations, one with the + and one with the -\r\n" );
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document.write( " and \r\n" );
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document.write( "Solving the first one\r\n" );
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document.write( "Get 0 on the right:\r\n" );
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document.write( "Factor the left side by thinking of two whole numbers which\r\n" );
document.write( "have product 12 and difference 4.  They are 6 and 2.  So\r\n" );
document.write( "we write\r\n" );
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document.write( "  \r\n" );
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document.write( "Then we put in the signs so that if we were to FOIL it out\r\n" );
document.write( "we would get the middle term  in the middle.\r\n" );
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document.write( "Then we use the zero-factor principle:\r\n" );
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document.write( "set each factor = 0\r\n" );
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document.write( " gives solution \r\n" );
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document.write( " gives solution \r\n" );
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document.write( "Solving the second one\r\n" );
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document.write( "Get 0 on the right:\r\n" );
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document.write( "Factor the left side by thinking of two whole numbers which\r\n" );
document.write( "have product 4 and sum 4.  They are 2 and 2.  So\r\n" );
document.write( "we write\r\n" );
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document.write( "Then we put in the signs so that if we were to FOIL it out\r\n" );
document.write( "we would get the middle term  in the middle.\r\n" );
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document.write( "Then we use the zero-factor principle:\r\n" );
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document.write( "set each factor = 0\r\n" );
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document.write( " gives solution \r\n" );
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document.write( "The second factor is the same, so we do not get an additional solution.\r\n" );
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document.write( "Checking in the original equation:\r\n" );
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document.write( "Checking \r\n" );
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document.write( "Checking \r\n" );
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document.write( "Checking \r\n" );
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document.write( "They are all solutions.\r\n" );
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document.write( "Edwin

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