document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=354730>Question 354730</A>: <I><SPAN STYLE=\"word-break: break-all;\"> We have been working on factoring trinomials and the problem I don't know how to solve is (x^2+4x-4)^2=64. I think what we're supposed to do is divide the exponent off both sides but I'm not sure. Were I get stuck is you're left with x^2+4x-4 on one side and that doesn't facter into two binomials. HELP ME! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253445 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253445\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> taking square root ___ x^2 + 4x - 4 = ±8\r<BR>\n" );
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document.write( "x^2 + 4x - 4 = 8 ___ x^2 + 4x - 12 = 0\r<BR>\n" );
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document.write( "x^2 + 4x - 4 = -8 ___ x^2 + 4x + 4 = 0\r<BR>\n" );
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document.write( "now factor both ...\r<BR>\n" );
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