document.write( "Question 354752: A dehydrated patient needs a 3.82% saline IV. Unfortunately, the hospital only has bags of 4% and 3% saline solutions. How many liters of each of these solutions should be mixed together to yield 5 liters of the desired concentration?\r
\n" ); document.write( "\n" ); document.write( "So far I've come up with this:\r
\n" ); document.write( "\n" ); document.write( "x= 4% solution; y= 3% solution
\n" ); document.write( "x + y = 5
\n" ); document.write( "4x + 3(5-x) = 3.82
\n" ); document.write( "4x + 15 -3x = 3.82 subtracting 15 from both sides
\n" ); document.write( "1x = -11.18
\n" ); document.write( "x= -11.18
\n" ); document.write( "

Algebra.Com's Answer #253436 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A dehydrated patient needs a 3.82% saline IV. Unfortunately, the hospital only has bags of 4% and 3% saline solutions. How many liters of each of these solutions should be mixed together to yield 5 liters of the desired concentration?
\n" ); document.write( "So far I've come up with this:
\n" ); document.write( "x= 4% solution; y= 3% solution
\n" ); document.write( "---------
\n" ); document.write( "Quantity Eq::: x + y = 5 liters
\n" ); document.write( "Salt Eq::::::::4x + 3(5-x) = 3.82*5
\n" ); document.write( "4x + 15 -3x = 19.1
\n" ); document.write( "x = 4.1 liters (amt. of 4% solution needed in the mixture)
\n" ); document.write( "y = 5-4.1 = 0.9 liters (amt of 3% solution needed in the mixture)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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