document.write( "Question 354682: one number is three less than twice another. the sum of their squares is 74. find the number \n" ); document.write( "
Algebra.Com's Answer #253394 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
HI,
\n" ); document.write( "Let n be and (2n - 3) represent the numbers
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\n" ); document.write( "questions states***
\n" ); document.write( "\"n%5E2+%2B+%282n-3%29%5E2+=+74\"
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\n" ); document.write( "expand & simplify
\n" ); document.write( "\"n%5E2+%2B+4n%5E2+-12n+%2B+9+=+74\"
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\n" ); document.write( "\"+5n%5E2+-12n++-+65+=+0\"\r
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\n" ); document.write( "using quadratic formula to solve
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
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\n" ); document.write( "\"n+=+%2812+%2B-+sqrt%28+1444+%29%29%2F%2810%29=+%2812+%2B-+38%29%2F%2810%29\"
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\n" ); document.write( "n = -2.6 (does not qualify as the sum of the squares being 74 )
\n" ); document.write( "n = 5
\n" ); document.write( "*(2n - 3)= 7
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\n" ); document.write( "check your answer
\n" ); document.write( "25 + 49 = 74\r
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