document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=354639>Question 354639</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me solve this?\r<BR>\n" );
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document.write( "the sum of two numbers is 45. if 4 times the smaller is increased by 3 times the larger, the result is 150. Find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253376 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253376\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi,<BR>\n" );
document.write( "let n represent the smaller number.  Then (45-n) would be the larger<BR>\n" );
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document.write( "4n + 3(45-n) = 150<BR>\n" );
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document.write( "4n  + 3*45 -3n = 150<BR>\n" );
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document.write( "n + 135 = 150<BR>\n" );
document.write( "n = 15<BR>\n" );
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document.write( "15 and 30 are the numbers<BR>\n" );
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document.write( "check your answer<BR>\n" );
document.write( "60 + 90 = 150 </SPAN>\n" );
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