document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=354620>Question 354620</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A football field is rectangular with a perimeter of 1040 feet. the length is 200 feet more than the width. Find the length and the width of the field. (hint: p=2l+2w) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253366 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253366\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A football field is rectangular with a perimeter of 1040 feet. the length is 200 feet more than the width. Find the length and the width of the field. (hint: p=2l+2w)<BR>\n" );
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document.write( "Let the width be \"w\".<BR>\n" );
document.write( "Then the length is \"w+200\"<BR>\n" );
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document.write( "P = 2(l+w)<BR>\n" );
document.write( "1040 = 2(w+200 + w)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "520 = 2w+200<BR>\n" );
document.write( "2w = 320<BR>\n" );
document.write( "w = 160 (width)<BR>\n" );
document.write( "l = w+200 = 360 (length)<BR>\n" );
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document.write( "cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
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