document.write( "Question 39896This question is from textbook Beginning Algebra
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document.write( ": If the sides of a square are decreased by 2 cm, the area is decreased by 36 cm^2. What were the dimensions of the original square?
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Algebra.Com's Answer #25335 by Fermat(136)![]() ![]() You can put this solution on YOUR website! If what you have is a square, then both the sides have the same size. \n" ); document.write( "Let the size of the square be x. \n" ); document.write( "Then the area of the square is, \n" ); document.write( "A = x * x = x^2 \n" ); document.write( "A = x^2 \n" ); document.write( "======= \n" ); document.write( "The new sides of the square are now x-2. \n" ); document.write( "The new area of the square is therefore, \n" ); document.write( "A2 = (x-2) * (x-2) = (x-2)^2 \n" ); document.write( "A2 = (x-2)^2 \n" ); document.write( "============ \n" ); document.write( "We are told that the new area, A2 is 36 cm^2 less than the original square. So we can write, \n" ); document.write( "A2 = A - 36 \n" ); document.write( "Substituting for A = x^2 and A2 = (x-2)^2, we get \n" ); document.write( "(x-2)^2 = x^2 - 36 \n" ); document.write( "now exand the brackets on the lhs, \n" ); document.write( "x^2 - 4x + 4 = x^2 - 36 \n" ); document.write( "subtract x^2 from both sides, \n" ); document.write( "-4x + 4 = -36 \n" ); document.write( "change the signs of all the terms, \n" ); document.write( "4x - 4 = 36 \n" ); document.write( "add 4 to both sides, \n" ); document.write( "4x = 40 \n" ); document.write( "divide both sides by 4, \n" ); document.write( "x = 10 cm \n" ); document.write( "========= \n" ); document.write( " |