document.write( "Question 354511: Solve for x: \r
\n" ); document.write( "\n" ); document.write( "log 2,(x+6) + log 2,(x-1) = 3\r
\n" ); document.write( "\n" ); document.write( "Thank you for your help! \n" ); document.write( "

Algebra.Com's Answer #253315 by robertb(5830) $\"\"$ $\"About$

You can put this solution on YOUR website!
log 2,(x+6) + log 2,(x-1) = 3
\n" ); document.write( "log 2,(x+6)(x-1) = 3
\n" ); document.write( "log 2, $\"%28x%5E2%2B5x-6%29\"$ = 3. This is the same as
\n" ); document.write( " $\"x%5E2%2B5x-6+=+2%5E3\"$ ,
\n" ); document.write( " $\"x%5E2%2B5x-6+=+8\"$ ,
\n" ); document.write( " $\"x%5E2%2B5x-14+=+0\"$ ,
\n" ); document.write( " $\"%28x%2B7%29%28x-2%29+=+0\"$ .
\n" ); document.write( "This gives $\"x+=+-7\"$ or $\"x+=+2\"$ . The first value won't satisfy the original equation, so the final answer is $\"x+=2\"$ . \n" ); document.write( "

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