document.write( "Question 354497: can you help me with this exercise, please? \r
\n" ); document.write( "\n" ); document.write( "solve for x: \r
\n" ); document.write( "\n" ); document.write( "ln e^(sqrt(x-2))= 6\r
\n" ); document.write( "\n" ); document.write( "Thank You!! \n" ); document.write( "

Algebra.Com's Answer #253309 by robertb(5830) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"ln+e%5E%28sqrt%28x-2%29%29=+6\"$ . The ln and the base e will just cancel each other out, to give
\n" ); document.write( " $\"sqrt%28x-2%29+=+6\"$ . Squaring both sides, we get
\n" ); document.write( " $\"x-2+=+36\"$ ,
\n" ); document.write( " $\"x+=+38\"$ . Checking this value against the original equation shows that indeed it is the solution to the equation.
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