document.write( "Question 354499: Can you help me, please?\r
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\n" ); document.write( "\n" ); document.write( "log(x+9) + log x = 1 \n" ); document.write( "

Algebra.Com's Answer #253302 by robertb(5830) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"log%28%28x%2B9%29%29%2B+log+x+=+1\"$ ,
\n" ); document.write( " $\"log%28x%28x%2B9%29%29+=+1\"$ ,
\n" ); document.write( " $\"10%5E1+=+x%28x%2B9%29\"$ ,or
\n" ); document.write( " $\"x%5E2%2B9x-10=0\"$
\n" ); document.write( " $\"%28x%2B10%29%28x-1%29=0\"$ ,
\n" ); document.write( " $\"x+=+-10\"$ , or $\"x+=+1\"$ .
\n" ); document.write( "Eliminate $\"x+=+-10\"$ , as it is an extraneous root (won't satisfy the original equation.) Therefore the solution is $\"x+=+1\"$ . \n" ); document.write( "

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