document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=354476>Question 354476</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ellen wishes to mix candy worth $1.80 per pound with candy worth $2.40 per pound to form 48 pounds of a mixture worth $2.00 per pound. How many pounds of the more expensive candy should she use. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253293 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253293\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> candy worth $1.80 per pound --- let the quantity be x lbs<BR>\n" );
document.write( "candy worth $2.40 per pound ---- this will be 48-x lbs<BR>\n" );
document.write( "Mix 48 pounds of a mixture worth $2.00 per pound.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "1.80x+2.4(48-x)=48*2<BR>\n" );
document.write( "1.80x+115.2-2.4x=96<BR>\n" );
document.write( "0.6x=115.2-96<BR>\n" );
document.write( "0.6x=19.2<BR>\n" );
document.write( "x=32 lbs of $1.80<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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