document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=354376>Question 354376</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A mother is five times as old as her son If twice the age of the son is 3 years less than half of the age of the mother how old are they </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253292 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253292\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let son be x years<BR>\n" );
document.write( "mother will be 5x years.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "2x = (1/2)*5x-3<BR>\n" );
document.write( "2x=5x/2 -3<BR>\n" );
document.write( "2x=(5x-6)/2<BR>\n" );
document.write( "4x=5x-6<BR>\n" );
document.write( "5x-4x=6<BR>\n" );
document.write( "x= 6 son's age<BR>\n" );
document.write( "mother is 5*6= 30 years<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );