document.write( "Question 354474: Ruth is twice as old as Pat. In 4 years Ruth will be three times as old as Pat was 3 years ago. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #253291 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Ruth is twice as old as Pat. In 4 years Ruth will be three times as old as Pat was 3 years ago. How old is each now? \n" ); document.write( ".. \n" ); document.write( "let Pat's age be x years \n" ); document.write( "Ruth's age will be 2x \n" ); document.write( "... \n" ); document.write( "after 4 years ruth will be 2x+4 \n" ); document.write( "... \n" ); document.write( "3 years ago pat was x-3 years \n" ); document.write( "... \n" ); document.write( "2x+4=3(x-3) \n" ); document.write( "2x+4=3x-9 \n" ); document.write( "2x-3x=-9-4 \n" ); document.write( "-x=-13 \n" ); document.write( "x= 13 years Pat's age. \n" ); document.write( "Ruth's age = 2x = 26 years \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |