document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=354463>Question 354463</A>: <I><SPAN STYLE=\"word-break: break-all;\"> given problem m = 3/4 , (1,-2)\r<BR>\n" );
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document.write( "y-(-2) = 3/4(x-1)\r<BR>\n" );
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document.write( "i don't know how to correctly solve this </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253285 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253285\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I presume you need equation of line<BR>\n" );
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document.write( "m=3/4 passing through point (1,-2)<BR>\n" );
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document.write( "y=mx+b<BR>\n" );
document.write( "first we find b by plugging the values of x,y,m in the equation<BR>\n" );
document.write( "-2=3/4*1 +b<BR>\n" );
document.write( "-2-3/4 =b<BR>\n" );
document.write( " -11/4= b<BR>\n" );
document.write( "...<BR>\n" );
document.write( "y=3x/4 -11/4 is the equation of the line passing through (1,-2)<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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