document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39900>Question 39900</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Towering antennae. <BR>\n" );
document.write( "A guy wire of length 50 feet is attached to the ground and to the top of an antenna. The height of the antenna is 10 feet larger than the distance from the base of the antenna to the point where the guy wire is attached to the ground. What is the height of the antenna?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25328 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25328\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X~2+(X+10)~2=50~2 OE X~2+X~2+20X+100=2500 OR 2X~2+20X-2400=0 OR X~2+10X-1200=0\r<BR>\n" );
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document.write( "OR (X+40)(X-30)=0 OR X=30 FEET FROM THE BASE TO THE GUY WIRE & 10+30=40 FEET FOR THE HEIGHT OF THE ANTENNA. </SPAN>\n" );
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