document.write( "Question 354447: Stan and Hilda can mow the lawn in 40 min if they work together. If Hilda works twice as fast as Stan, how long would it take Stan to mow the lawn alone? \n" ); document.write( "
Algebra.Com's Answer #253277 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Stan and Hilda can mow the lawn in 40 min if they work together. If Hilda works twice as fast as Stan, how long would it take Stan to mow the lawn alone? \n" ); document.write( "------------ \n" ); document.write( "Together rate = 1/40 job/min \n" ); document.write( "Hilda time = x: Hilda rate = 1/x job/min \n" ); document.write( "Stan time = 2x; Stan rate = 1/(2x) job/min \n" ); document.write( "------------------------------ \n" ); document.write( "Equation: \n" ); document.write( "rate + rate = together rate \n" ); document.write( "1/x + 1/2x = 1/40 \n" ); document.write( "----- \n" ); document.write( "Multiply thru by 40x to get: \n" ); document.write( "40 +20 = x \n" ); document.write( "x = 60 minutes \n" ); document.write( "---- \n" ); document.write( "Stan time = 2x = 2 hrs \n" ); document.write( "============================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |