document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=354372>Question 354372</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you solve: the sum of 4 times lisa's age and 7 times janes age is 169. jane is 1 year more than twice as old as lisa is. find each of their ages </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253236 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253236\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4x+7(2x+1)=169<BR>\n" );
document.write( "4x+14x+7=169<BR>\n" );
document.write( "18x=162<BR>\n" );
document.write( "x=9<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "4*9+7(2*9+1)=169<BR>\n" );
document.write( "36+126+7=169<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "L=x=9<BR>\n" );
document.write( "A=2x+1=19 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );