document.write( "Question 354345: 3|2x| less than or equal to 12\r
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Algebra.Com's Answer #253231 by dejaview(1)![]() ![]() You can put this solution on YOUR website! |2x| Absolute value of 2x is going to be positive \n" ); document.write( "3(2x) ≤ 12 Multiply 3 and 2x \n" ); document.write( "6x ≤ 12 by dividing 6 on both side \n" ); document.write( "x ≤ 2 solution \n" ); document.write( " |