document.write( "Question 354257: Please please please help. Due tonight. I have done all of the others, but cannot get this one.\r
\n" ); document.write( "\n" ); document.write( "How many committees can be formed from a group of 9 doctors of each committee consists of 7 doctors. I must also explain how I ca,e to this conclusion.
\n" ); document.write( "Thank-you so much n advance.
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Algebra.Com's Answer #253203 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
each committee leaves out 2 of the 9 doctors\r
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\n" ); document.write( "\n" ); document.write( "there are 9 ways to leave out one doctor\r
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\n" ); document.write( "\n" ); document.write( "for each of those 9 ways , there are 8 ways to leave out the second doctor
\n" ); document.write( "___ so 72 ways
\n" ); document.write( "___ BUT ... leaving out Dr. Smith and then Dr. Jones , is the SAME as leaving out Dr. Jones and then Dr. Smith\r
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\n" ); document.write( "\n" ); document.write( "so the possible committees is 72/2
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