document.write( "Question 39873: Hello Math Wizards! I have the answer to the ff: problems but I want to confirm that my answer is correct.\r
\n" ); document.write( "\n" ); document.write( "Find the center, vertices and foci of the ellipse given by each equation.Sketch the graph.\r
\n" ); document.write( "\n" ); document.write( "1. x^2/49 + y^2/36 =1\r
\n" ); document.write( "\n" ); document.write( "2. ( x + 3 )^2/9 + ( y - 2)^2/16 = 1\r
\n" ); document.write( "\n" ); document.write( "Thanks,
\n" ); document.write( "Jo\r
\n" ); document.write( "\n" ); document.write( "
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Algebra.Com's Answer #25319 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Find the center, vertices and foci of the ellipse given by each equation.Sketch the graph.
\n" ); document.write( "1. x^2/49 + y^2/36 =1
\n" ); document.write( "a=7, b=6
\n" ); document.write( "a^2=b^2+c^2
\n" ); document.write( "49=36+c^2
\n" ); document.write( "c=sqrt(13)
\n" ); document.write( "Center is at (0.0)
\n" ); document.write( "Vertices are at (7,0),(-7,0)
\n" ); document.write( "Foci are at (sqrt(13),0), (-sqrt(13),0)\r
\n" ); document.write( "\n" ); document.write( "2. ( x + 3 )^2/9 + ( y - 2)^2/16 = 1
\n" ); document.write( "Center is at (-3,2)
\n" ); document.write( "a=4,b=3
\n" ); document.write( "c^2=a^2-b^2
\n" ); document.write( "c^2=16-9=7
\n" ); document.write( "c=sqrt(7)
\n" ); document.write( "Vertices are at (-3,2-4), (-3,2+4)
\n" ); document.write( "Foci are at (-3,2-sqrt7) and (-3,2+sqrt7)
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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