document.write( "Question 354225: How do I write the equation of a line in slope-intercept form and standard form containing point (5,1) and is perpendicular to y=5x-4? \n" ); document.write( "

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How do I write the equation of a line in slope-intercept form and standard form containing point (5,1) and is perpendicular to y=5x-4?
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\n" ); document.write( "The slope of:
\n" ); document.write( "y=5x-4
\n" ); document.write( "is 5
\n" ); document.write( "we know this because it is in the \"slope-intercept\" form:
\n" ); document.write( "y=mx+b
\n" ); document.write( ".
\n" ); document.write( "Our new line is perpendicular to this so it must be
\n" ); document.write( "5m = -1
\n" ); document.write( "m = -1/5 (negative reciprocal)
\n" ); document.write( ".
\n" ); document.write( "With (5,1) and the slope (-1/5) plug it into \"point-slope\" form:\r
\n" ); document.write( "\n" ); document.write( "y - y1 = m(x - x1)\r
\n" ); document.write( "\n" ); document.write( "y - 1 = (-1/5)(x - 5)\r
\n" ); document.write( "\n" ); document.write( "y - 1 = (-1/5)x + 1
\n" ); document.write( "y = (-1/5)x + 2 (slope-intercept form)
\n" ); document.write( ".
\n" ); document.write( "standard form:
\n" ); document.write( "(1/5)x + y = 2 \n" ); document.write( "

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