document.write( "Question 354154: when fritz drives to work his trip takes 48 minutes, but when he takes the train it takes 40 minutes. find the distance fritz travels to work if the train travels an average of 6 mph faster than his driving. \n" ); document.write( "
Algebra.Com's Answer #253137 by stanbon(75887)\"\" \"About 
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when fritz drives to work his trip takes 48 minutes, but when he takes the train it takes 40 minutes. find the distance fritz travels to work if the train travels an average of 6 mph faster than his driving.
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\n" ); document.write( "Drive DATA:
\n" ); document.write( "time = 48 min ; distance = x miles ; rate = x/48 miles per minute
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\n" ); document.write( "Train DATA:
\n" ); document.write( "time = 40 min ; distance = x miles ; rate = x/40 miles per min
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\n" ); document.write( "Equation:
\n" ); document.write( "train rate - drive rate = 6/60 miles per minute
\n" ); document.write( "x/40 - x/48 = 1/10
\n" ); document.write( "---
\n" ); document.write( "Multiply thru by 10*48*40 to get:
\n" ); document.write( "10*48x - 10*40x = 48*40
\n" ); document.write( "80x = 48*40
\n" ); document.write( "x = 24 miles
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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