document.write( "Question 39876: X/3 + 1/6 (less than or equal to) 2x + 3/2 \n" ); document.write( "
Algebra.Com's Answer #25313 by fractalier(6550)\"\" \"About 
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Let us clear all of the fractions in
\n" ); document.write( "x/3 + 1/6 ≤ 2x + 3/2
\n" ); document.write( "by multiplying by the lowest common denominator, which is 6...we get
\n" ); document.write( "6[x/3 + 1/6 ≤ 2x + 3/2]
\n" ); document.write( "2x + 1 ≤ 12x + 9
\n" ); document.write( "-8 ≤ 10x
\n" ); document.write( "-4/5 ≤ x or
\n" ); document.write( "x ≥ -4/5
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