document.write( "Question 39876: X/3 + 1/6 (less than or equal to) 2x + 3/2 \n" ); document.write( "
Algebra.Com's Answer #25313 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! Let us clear all of the fractions in \n" ); document.write( "x/3 + 1/6 ≤ 2x + 3/2 \n" ); document.write( "by multiplying by the lowest common denominator, which is 6...we get \n" ); document.write( "6[x/3 + 1/6 ≤ 2x + 3/2] \n" ); document.write( "2x + 1 ≤ 12x + 9 \n" ); document.write( "-8 ≤ 10x \n" ); document.write( "-4/5 ≤ x or \n" ); document.write( "x ≥ -4/5 \n" ); document.write( " |