document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=354082>Question 354082</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the diameter of a wheel is 2 feet.approximately how many times it rotates to cross 2 miles? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253097 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253097\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> diameter = 2feet<BR>\n" );
document.write( "cicumference = pi*d<BR>\n" );
document.write( "=3.142*2<BR>\n" );
document.write( "=6.284 feet.<BR>\n" );
document.write( "when the wheel makes one rotation it travels 6.284 feet.<BR>\n" );
document.write( "it has to travel 2 miles <BR>\n" );
document.write( "1 mile = 5280 feet<BR>\n" );
document.write( "2 miles = 10560 feet<BR>\n" );
document.write( "number of rotations = 10560/6.284<BR>\n" );
document.write( "= 1680 rotations<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );