document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=354069>Question 354069</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of an angle is 15 less than 2 times the other angle. If the two angles are complementary angles, find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253088 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253088\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if one angle is x<BR>\n" );
document.write( "the other angle = 2x-15<BR>\n" );
document.write( "..<BR>\n" );
document.write( "They are complementory angles<BR>\n" );
document.write( "x+2x-15=90<BR>\n" );
document.write( "3x-15 =90<BR>\n" );
document.write( "3x=90+15<BR>\n" );
document.write( "3x=105<BR>\n" );
document.write( "x=105/3<BR>\n" );
document.write( "x=35 <BR>\n" );
document.write( "the other angle = 55<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );