document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=354041>Question 354041</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bacteria culture starts with 1,000 bacteria and doubles in size every 2 hours. Find an exponential model for the size of the culture as a function of time t in hours.<BR>\n" );
document.write( "f(t) =<BR>\n" );
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document.write( "Use the model to predict how many bacteria there will be after 2 days.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253059 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253059\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A bacteria culture starts with 1,000 bacteria and doubles in size every 2 hours. Find an exponential model for the size of the culture as a function of time t in hours.<BR>\n" );
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document.write( "P = Noe^(kt)<BR>\n" );
document.write( "where<BR>\n" );
document.write( "P is amount after t time<BR>\n" );
document.write( "No is the initial amount<BR>\n" );
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document.write( "No is 1000<BR>\n" );
document.write( "P is 2000<BR>\n" );
document.write( "t = 2<BR>\n" );
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document.write( "2000 = 1000e^(2k)<BR>\n" );
document.write( "2= e^(2k)<BR>\n" );
document.write( "ln(2) = 2k<BR>\n" );
document.write( "ln(2)/2 = k <BR>\n" );
document.write( "0.34657 =k<BR>\n" );
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document.write( "F(t) = 1000e(0.34657t)<BR>\n" );
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document.write( "Use the model to predict how many bacteria there will be after 2 days.<BR>\n" );
document.write( "2 days in terms of hours is 48 hours<BR>\n" );
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document.write( "F(48) = 1000e(0.34657*48)\r<BR>\n" );
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document.write( "F(48) = 1000e(-16.63553)\r<BR>\n" );
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document.write( "F(48) = 1.6778*10^10 </SPAN>\n" );
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