document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=354002>Question 354002</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how to Simplifying a ratio of polynomials like 3v^2-48/v^2-6v+8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253042 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253042\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "This 3v^2-48/v^2-6v+8 can be rewritten as:<BR>\n" );
document.write( "3(v^2-16)/(v-2)(v-4)<BR>\n" );
document.write( "Now the numerator can be rewritten as:<BR>\n" );
document.write( "3(v-4)(v+4)/(v-2)(v-4)<BR>\n" );
document.write( "Then we can cancel out to give us:<BR>\n" );
document.write( "3(v+4)/(v-2)<BR>\n" );
document.write( "Make sense?<BR>\n" );
document.write( "RJ<BR>\n" );
document.write( "www.math-unlock.com </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );