document.write( "Question 353986: A triangle has a perimeter of 44 cm. The third side is 3 cm longer than twice the first side. The second side is 4 cm shorter than twise the first side. What is the length of the second side? \n" ); document.write( "
Algebra.Com's Answer #253021 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! PERIMETER=44 \n" ); document.write( "S3=2S1+3 \n" ); document.write( "S2=2S1-4 \n" ); document.write( "S1+S2+S3=44 \n" ); document.write( "S1+(2S1-4)+(2S1+3)=44 \n" ); document.write( "S1+2S1-4+2S1+3=44 \n" ); document.write( "5S1=44+4-3 \n" ); document.write( "5S1=45 \n" ); document.write( "S1=45/5 \n" ); document.write( "S1=9 cm. for S1. \n" ); document.write( "S2=2*9-4=18-4=14 cm. for S2. \n" ); document.write( "S3=2*9+3=18=3=21 cm. for S3. \n" ); document.write( "Proof: \n" ); document.write( "9+14+21=44 \n" ); document.write( "44=44 \n" ); document.write( " \n" ); document.write( " |