document.write( "Question 353986: A triangle has a perimeter of 44 cm. The third side is 3 cm longer than twice the first side. The second side is 4 cm shorter than twise the first side. What is the length of the second side? \n" ); document.write( "
Algebra.Com's Answer #253021 by checkley77(12844)\"\" \"About 
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PERIMETER=44
\n" ); document.write( "S3=2S1+3
\n" ); document.write( "S2=2S1-4
\n" ); document.write( "S1+S2+S3=44
\n" ); document.write( "S1+(2S1-4)+(2S1+3)=44
\n" ); document.write( "S1+2S1-4+2S1+3=44
\n" ); document.write( "5S1=44+4-3
\n" ); document.write( "5S1=45
\n" ); document.write( "S1=45/5
\n" ); document.write( "S1=9 cm. for S1.
\n" ); document.write( "S2=2*9-4=18-4=14 cm. for S2.
\n" ); document.write( "S3=2*9+3=18=3=21 cm. for S3.
\n" ); document.write( "Proof:
\n" ); document.write( "9+14+21=44
\n" ); document.write( "44=44
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