document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=353926>Question 353926</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many liters of some solution containing 15% of chemicals should be added to the same kind of solution with 65% chemicals to obtain 10 liters of solution with 50% of chemicals? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253019 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253019\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .65X+.15(10-X)=.50*10<BR>\n" );
document.write( ".65X+1.5-.15X=5<BR>\n" );
document.write( ".50X=5-1.5<BR>\n" );
document.write( ".50X=3.5<BR>\n" );
document.write( "X=3.5/.50<BR>\n" );
document.write( "X=7 LITERS OF THE 65% SOLUTION IS USED.<BR>\n" );
document.write( "10-7=3 LITERS OF THE 15% SOLUTION IS USED.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( ".65*7+.15*3=.50*10<BR>\n" );
document.write( "4.55+.45=5<BR>\n" );
document.write( "5=5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );