document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=353928>Question 353928</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2)	A train travels 300 km in the same time that a plane covers 800 km. If the speed of the plane is 20 km per hr less than 3 times the speed of the train, find both speeds.\r<BR>\n" );
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document.write( "help me please! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253018 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253018\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "300=RT FOR THE TRAIN<BR>\n" );
document.write( "OR: T=300/R<BR>\n" );
document.write( "800=(3R-20)T FOR THE PLANE<BR>\n" );
document.write( "OR: T=800/(3R-20)<BR>\n" );
document.write( "BECAUSE THE TIMES ARE EQUAL WE HAVE:<BR>\n" );
document.write( "300/R=800/(3R-20) <BR>\n" );
document.write( "800R=300(3R-20)<BR>\n" );
document.write( "800R=900R-6,000<BR>\n" );
document.write( "800R-900R=-6,000<BR>\n" );
document.write( "-100R=-6,000<BR>\n" );
document.write( "R=-6,000/-100<BR>\n" );
document.write( "R=60 KMH FOR THE TRAIN.<BR>\n" );
document.write( "3*60-20=180-20=160KMH FOR THE PLANE.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "300/60=800/160<BR>\n" );
document.write( "5=5 HOURS FOR THE TRIPS.\r<BR>\n" );
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