document.write( "Question 353894: I have a hard exponent quadratic question.\r
\n" );
document.write( "\n" );
document.write( "5x^2/3 + 2x^4/3 -13 =0\r
\n" );
document.write( "\n" );
document.write( "My first inclination was to rearrange the terms to...\r
\n" );
document.write( "\n" );
document.write( "2x^4/3 + 5x^2/3 -13 =0\r
\n" );
document.write( "\n" );
document.write( "This puts it in the right order for substitution / y= x^2/3\r
\n" );
document.write( "\n" );
document.write( "Thus... 2y^2 + 5y -13 =0\r
\n" );
document.write( "\n" );
document.write( "This is where I'm stuck. I don't know how to unfold the answer with the unusual powers.\r
\n" );
document.write( "\n" );
document.write( "Thanks for your help.
\n" );
document.write( "Neil \n" );
document.write( "
Algebra.Com's Answer #252978 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Well, you are ok so far but now you can use the quadratic formula ( \n" ); document.write( " \n" ); document.write( "When you evaluate this you will get: \n" ); document.write( " \n" ); document.write( "Now you will need to substitute \n" ); document.write( " \n" ); document.write( "To find x, raise both sides of each solution to the \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "It would be advisable to check these solutions in your original equations. \n" ); document.write( " |