document.write( "Question 353894: I have a hard exponent quadratic question.\r
\n" ); document.write( "\n" ); document.write( "5x^2/3 + 2x^4/3 -13 =0\r
\n" ); document.write( "\n" ); document.write( "My first inclination was to rearrange the terms to...\r
\n" ); document.write( "\n" ); document.write( "2x^4/3 + 5x^2/3 -13 =0\r
\n" ); document.write( "\n" ); document.write( "This puts it in the right order for substitution / y= x^2/3\r
\n" ); document.write( "\n" ); document.write( "Thus... 2y^2 + 5y -13 =0\r
\n" ); document.write( "\n" ); document.write( "This is where I'm stuck. I don't know how to unfold the answer with the unusual powers.\r
\n" ); document.write( "\n" ); document.write( "Thanks for your help.
\n" ); document.write( "Neil
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Algebra.Com's Answer #252978 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Well, you are ok so far but now you can use the quadratic formula (\"y+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\") to solve for y. In this problem, a = 2, b = 5, and c = -13, so...
\n" ); document.write( "\"y+=+%28-5%2B-sqrt%285%5E2-4%282%29%28-13%29%29%29%2F2%282%29\"
\n" ); document.write( "When you evaluate this you will get:
\n" ); document.write( "\"y+=+-4.089\" or \"1.589\"
\n" ); document.write( "Now you will need to substitute \"y+=+x%5E%282%2F3%29\", so...
\n" ); document.write( "\"x%5E%282%2F3%29+=+-4.089\" or \"x%5E%282%2F3%29+=+1.589\"
\n" ); document.write( "To find x, raise both sides of each solution to the \"3%2F2\" (the reciprocal of \"2%2F3%29\") power.
\n" ); document.write( "\"x+=+%28-4.089%29%5E%283%2F2%29\" or \"x+=+%281.589%29%5E%283%2F2%29\" Use your calculator to evaluate to get:
\n" ); document.write( "\"x+=+-8.268i\" or \"x+=+2\"
\n" ); document.write( "It would be advisable to check these solutions in your original equations.
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