document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=353869>Question 353869</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 4 more than three times a smaller number. If twice the larger number is decreased by three times the smaller number, the result is 32. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #252958 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=252958\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "Let's set up x being the smaller number and y will be the larger one. We can set up 2 equation as: <BR>\n" );
document.write( "y=3x+4<BR>\n" );
document.write( "2y-3x=32<BR>\n" );
document.write( "rewritten as:<BR>\n" );
document.write( "y-3x=4<BR>\n" );
document.write( "2y-3x=32<BR>\n" );
document.write( "Multiply the first equation by -2 to get:<BR>\n" );
document.write( "-2y+6x=-8<BR>\n" );
document.write( "Add this to the second equation:<BR>\n" );
document.write( "3x=24<BR>\n" );
document.write( "Divide by 3 to get:<BR>\n" );
document.write( "x=8<BR>\n" );
document.write( "Therefore y=28<BR>\n" );
document.write( "Make sense?<BR>\n" );
document.write( "RJ<BR>\n" );
document.write( "www.math-unlock.com </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );