document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=353860>Question 353860</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many liters of a 20% dye solution and a 50% solution should be mixed to obtain 6 liters of a 40% solution </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #252954 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=252954\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi,<BR>\n" );
document.write( "Let x be the amount of the 50% total solution. then (6L-x) would be the amount of the 20% total solutiom<BR>\n" );
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document.write( "question states<BR>\n" );
document.write( ".50x + .20(6L-x)=.40*6L<BR>\n" );
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document.write( "simplify and solve<BR>\n" );
document.write( ".30x = .40*6L - .20*6L\r<BR>\n" );
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document.write( "x (the amount of the 50% total solution)= 4L<BR>\n" );
document.write( "the amount of the 20% total solution = 2L<BR>\n" );
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