document.write( "Question 353826: One can fill a tank in 4 hours. Together with a second pipe, the tank can be filled in 3 hours. How long would it take the second pipe alone to fill the tank? \n" ); document.write( "
Algebra.Com's Answer #252943 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
One can fill a tank in 4 hours. Together with a second pipe, the tank can be filled in 3 hours. How long would it take the second pipe alone to fill the tank?
\n" ); document.write( "---
\n" ); document.write( "1st pipe rate = 1/4 job/hr
\n" ); document.write( "---
\n" ); document.write( "Together rate = 1/3 job/hr
\n" ); document.write( "----
\n" ); document.write( "2nd pipe rate = 1/x job/hr
\n" ); document.write( "----------------------------------
\n" ); document.write( "Equation:
\n" ); document.write( "rate + rate = together rate
\n" ); document.write( "1/4 + 1/x = 1/3
\n" ); document.write( "Multiply thru by 12x to get:
\n" ); document.write( "3x + 12 = 4x
\n" ); document.write( "x = 12 hrs (time required for the 2nd pipe to do the job alone)
\n" ); document.write( "===========================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" ); document.write( "
\n" );