document.write( "Question 353826: One can fill a tank in 4 hours. Together with a second pipe, the tank can be filled in 3 hours. How long would it take the second pipe alone to fill the tank? \n" ); document.write( "
Algebra.Com's Answer #252943 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! One can fill a tank in 4 hours. Together with a second pipe, the tank can be filled in 3 hours. How long would it take the second pipe alone to fill the tank? \n" ); document.write( "--- \n" ); document.write( "1st pipe rate = 1/4 job/hr \n" ); document.write( "--- \n" ); document.write( "Together rate = 1/3 job/hr \n" ); document.write( "---- \n" ); document.write( "2nd pipe rate = 1/x job/hr \n" ); document.write( "---------------------------------- \n" ); document.write( "Equation: \n" ); document.write( "rate + rate = together rate \n" ); document.write( "1/4 + 1/x = 1/3 \n" ); document.write( "Multiply thru by 12x to get: \n" ); document.write( "3x + 12 = 4x \n" ); document.write( "x = 12 hrs (time required for the 2nd pipe to do the job alone) \n" ); document.write( "=========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |