document.write( "Question 353843: Find the area of a right triangle whose legs have lengths which differ by 7 meters and whose hypotenuse is 17 meters long. (Show your solution using Quadratic Equation) \n" ); document.write( "
Algebra.Com's Answer #252939 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Find the area of a right triangle whose legs have lengths which differ by 7 meters and whose hypotenuse is 17 meters long. (Show your solution using Quadratic Equation) \n" ); document.write( ". \n" ); document.write( "Once you see \"right triangle\" you can apply the Pythagorean theorem. \n" ); document.write( ". \n" ); document.write( "Let x = shortest leg \n" ); document.write( "then \n" ); document.write( "x+7 = other leg \n" ); document.write( "17 = hypotenuse \n" ); document.write( ".\r \n" ); document.write( "\n" ); document.write( "x^2 + (x+7)^2 = 17^2\r \n" ); document.write( "\n" ); document.write( "x^2 + (x+7)(x+7) = 17^2\r \n" ); document.write( "\n" ); document.write( "x^2 + x^2+14x+49 = 289\r \n" ); document.write( "\n" ); document.write( "2x^2+14x+49 = 289\r \n" ); document.write( "\n" ); document.write( "2x^2+14x-240 = 0\r \n" ); document.write( "\n" ); document.write( "x^2+7x-120 = 0 (your quadratic)\r \n" ); document.write( "\n" ); document.write( "(x+15)(x-8) = 0\r \n" ); document.write( "\n" ); document.write( "x = {-15, 8}\r \n" ); document.write( "\n" ); document.write( "Throw out the negative solution leaving \n" ); document.write( "x = 8 meters (shortest leg) \n" ); document.write( "x+7 = 8+7= 15 meters (other leg)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Area is \n" ); document.write( "(1/2)bh \n" ); document.write( "(1/2)(8)(15) \n" ); document.write( "(4)(15) \n" ); document.write( "60 square meters \n" ); document.write( " |