document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=353827>Question 353827</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man deposited $2000 in a savings bank paying him a certain interest. At the end of the year he withdraw $150. At the end of the second year the amount dew to him was $1947.50. What was the rate of interest? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #252923 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=252923\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> $ 2000 in savings bank<BR>\n" );
document.write( "Let x% be the interest.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "interest obtained = 20x.<BR>\n" );
document.write( "he withdrew $150<BR>\n" );
document.write( "Balance in account after 1 year = 2000-150+20x = 1850+20x<BR>\n" );
document.write( "...<BR>\n" );
document.write( "Interest for second year = 0.01x(1850+20x)+1850+20x = 1947.50<BR>\n" );
document.write( "18.50x+0.2x^2+1850+20x=1947.50<BR>\n" );
document.write( "0.2x^2+38.50x=1947.50-1850<BR>\n" );
document.write( "0.2x^2+38.5x=97.5<BR>\n" );
document.write( "multiply by 10<BR>\n" );
document.write( "2x^2+385x-975 =0<BR>\n" );
document.write( "discriminant = 156025<BR>\n" );
document.write( "solve by quadratic formula<BR>\n" );
document.write( "x1= 2.5%<BR>\n" );
document.write( "x2= -195 ignore negative value\r<BR>\n" );
document.write( "\n" );
document.write( "....<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );