document.write( "Question 353819: The volume of a circular disk varies as its thickness and the square of the diameter of its face. Two metallic disks having the thicknesses ¼ inch and 1/6 inch and the diameters of 5 inches and 3 inches, respectively, are melted and recast into a single disk having a diameter of 6 inches. Find its thickness. \n" ); document.write( "
Algebra.Com's Answer #252921 by mananth(16946)\"\" \"About 
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1/4 inch - 5 \" diameter = 2.5 inch radius.
\n" ); document.write( "volume = pi*2.5*2.5*1/4
\n" ); document.write( "V= 4.91 cu.in
\n" ); document.write( "1/6 inch -3 \"diamter = 1.5\" radius
\n" ); document.write( "V= pi*1.5*1.5*1/6
\n" ); document.write( "= 1.18 cu.in
\n" ); document.write( "Total = 4.91+1.18=6.09
\n" ); document.write( "...
\n" ); document.write( "Volume = pi*3*3*h
\n" ); document.write( "6.09/(pi*3*3)=h
\n" ); document.write( "h= 0.215inch or 1/5\"
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "
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